Calendar For 2005

Calendar For 2005 - But, feb 2004 not included because we are calculating from march 2004 to march 2005. Calendar questions & answers for bank exams : On 31st december, 2005 it was saturday. Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. The dates 3rd april, 2005; Add +6 to the given year (i.e 2005 + 6) = 2011.

Therfore, the calendar for the year 2005 will be same for the year 2011 Therfore, on 31st december 2009, it was thursday. Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. Given year is 2005, which is a non leap year. Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

The dates 3rd april, 2005; On 31st december, 2005 it was saturday. Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. Thus, on 1st jan, 2010 it is friday Add +11 to the given year (i.e 2005 + 11) = 2016, which is a leap year. 5th march, 2004 is sunday (1 day before to 5th march, 2005).

But, feb 2004 not included because we are calculating from march 2004 to march 2005. Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days. The dates 3rd april, 2005;

On 31St December, 2005 It Was Saturday.

So it has 1 odd day only. 5th march, 2004 is sunday (1 day before to 5th march, 2005). But, feb 2004 not included because we are calculating from march 2004 to march 2005. The dates 3rd april, 2005;

Given Year Is 2005, Which Is A Non Leap Year.

The indian independence day of which year among the following has the same property? The dates 3rd april, 2005; The dates 3rd april, 2005; Number of odd days from 2006 to 2009 = (1 + 1 + 2 + 1) = 5 days.

Given That, 5Th March, 2005 Is Monday.

Therfore, on 31st december 2009, it was thursday. The dates 3rd april, 2005; Add +11 to the given year (i.e 2005 + 11) = 2016, which is a leap year. Therfore, the calendar for the year 2005 will be same for the year 2011

Calendar Questions & Answers For Bank Exams :

Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days. Thus, on 1st jan, 2010 it is friday Add +6 to the given year (i.e 2005 + 6) = 2011. The day on 5th march, 2005 will be 1 day beyond the day on 5th march, 2004.

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